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Http Error 403 Forbidden Python

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Solution: import urllib2 url = "http://www.gocomics.com/calvinandhobbes" req = urllib2.Request(url, headers={'User-Agent' : "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/534.30 (KHTML, like Gecko) Ubuntu/11.04 Chromium/12.0.742.112 Chrome/12.0.742.112 Safari/534.30"}) con = urllib2.urlopen(req) print con.read() Note to Self We indicate this by providing None as the realm argument to the add_password method. The HTTPError instance raised will have an integer ‘code' attribute, which corresponds to the error sent by the server. Can someone help me be able to connect to it. have a peek here

search engine ranker:Spot on with this wr... Can you please help. This is probably temporary and should be fixed soon. current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. http://stackoverflow.com/questions/13303449/urllib2-httperror-http-error-403-forbidden

Python Requests 403 Forbidden

This tutorial focuses on the most common case, HTTP. worked for me too –DenisFLASH Aug 27 '15 at 10:20 add a comment| up vote 0 down vote Here are some notes I gathered on urllib when I was studying python-3: It is currently an http.client.HTTPMessage instance. To the right, to the left, now rotate Why do we use the electron volt?

This is through the ProxyHandler, which is part of the normal handler chain when a proxy setting is detected. What does an exclamation mark mean in diff output? import urllib2 page=urllib2.urlopen(url) content=page.read() And i was into a small hobby project, it is all about fetching images from comic websites. Urllib2 User Agent asked 10 months ago viewed 925 times active 10 months ago Related 7HTTPError: HTTP Error 403: Forbidden41urllib2.HTTPError: HTTP Error 403: Forbidden-1HTTP Server Error 403.

This is done using similar steps to setting up a Basic Authentication handler: >>> proxy_support = urllib.request.ProxyHandler({}) >>> opener = urllib.request.build_opener(proxy_support) >>> urllib.request.install_opener(opener) Note Currently urllib.request does not support fetching Python Requests 403 Error By default the socket module has no timeout and can hang. Browse other questions tagged python python-3.x urllib or ask your own question. http://stackoverflow.com/questions/13055208/httperror-http-error-403-forbidden Join them; it only takes a minute: Sign up Python 3.4 urllib.request error (http 403) up vote 8 down vote favorite I'm trying to open and parse a html page.

Best way to remove rusted steel bolts from aluminum parts I got a paper to review from a journal that had rejected my earlier works, how to respond? Python Urllib Headers In [28]: import requests In [29]: r = requests.get(url) In [30]: r.status_code Out[30]: 200 share|improve this answer edited Mar 7 at 0:42 answered Mar 7 at 0:36 Padraic Cunningham 112k960116 geturl - this returns the real URL of the page fetched. In that case, it is convenient to use HTTPPasswordMgrWithDefaultRealm.

  1. The header looks like: WWW-Authenticate: SCHEME realm="REALM".
  2. The encoding is done using a function from the urllib.parse library.
  3. The above method worked for most of the websites, all except www.gocomics.com/calvinandhobbes.I got an error like this File "/usr/lib/python2.7/urllib2.py", line 518, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP
  4. You are a bot. –hobbs May 18 '13 at 18:00 add a comment| 3 Answers 3 active oldest votes up vote 26 down vote accepted This is probably because of mod_security
  5. Forbidden3Python HTTP Error 403 Forbidden1python urllib2.HTTPError: HTTP Error 403: Forbidden3Python3: urllib.error.HTTPError: HTTP Error 403: Forbidden0Python 3 urllib HTTP Error 403: FORBIDDEN with localhost using params2Python3 - urllib.error.HTTPError: HTTP Error 403: Forbidden1HTTP
  6. What to do when you are asked to perform an official review for a journal of a manuscript written by your supervisor?

Python Requests 403 Error

urllib uses the http.client library, which in turn uses the socket library. http://stackoverflow.com/questions/34957748/http-error-403-forbidden python python-3.x urllib share|improve this question edited Feb 8 '15 at 16:35 falsetru 177k23228275 asked Feb 8 '15 at 15:57 Belial 198110 add a comment| 2 Answers 2 active oldest votes Python Requests 403 Forbidden How to get last part of http link in Bash? Http Error Forbidden Python Openers and Handlers¶ When you fetch a URL you use an opener (an instance of the perhaps confusingly-named urllib.request.OpenerDirector).

may also be raised). HTTPError is the subclass of URLError raised in the specific case of HTTP URLs. navigate here However, even I made a list of 'User-Agent' and randomly choose one of them to construct a url, the website will sent me "urllib2.URLError: " or just why "Magento commerce" remove previous version of Magento c.e website from official website? Is it mandatory to define transitions on every possible alphabet in Deterministic Finite Automata? Yolk Urllib2.httperror: Http Error 403: Must Access Using Https Instead Of Http

top_level_url = "http://example.com/foo/" password_mgr.add_password(None, top_level_url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) # create "opener" (OpenerDirector instance) opener = urllib.request.build_opener(handler) # use the opener to fetch a URL opener.open(a_url) # Install the opener. How did I survive this shock? more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Check This Out This specifies the authentication scheme and a ‘realm'.

Can someone help me be able to connect to it. Urllib.error.httperror: Http Error 403: Forbidden more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Wikipedia is just treating your script as a bot and rejecting it.

except urllib.error.URLError as e: ...

You can create a new class called AppURLopener which overrides the user-agent with Mozilla. I've looked on the forum and tried some of the fixes and it doesn't seem to work. How did Smith get to see Cypher alone? Python Requests User Agent up vote 39 down vote favorite 23 I have a strange bug when trying to urlopen a certain page from Wikipedia.

print(e.read()) ... 404 b'\n\n\nPage Not Found\n ... Soldier mentioned in War Dogs Can steel be replaced with aluminum alloy in construction of buildings? Is there such thing as a "Black Box" that decrypts internet traffic? http://bookmarq.net/http-error/http-error-403-14-forbidden-iis.php To the right, to the left, now rotate Replace custom functions, leave built in functions untouched?

as for the target, google especially is a tough one, kinda hard to scrape, they have implemented many methods to prevent scraping. –andrean Jan 20 '15 at 6:40 | show 4 I've looked on the forum and tried some of the fixes and it doesn't seem to work. WWW-Authenticate: Basic realm="cPanel Users" The client should then retry the request with the appropriate name and password for the realm included as a header in the request. TIP: since this is exercise, choose a different, non restrictive site.




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